(2x^2)/(40)=0.0025

Solution for (2x^2)/(40)=0.0025 equation:

(2x^2)/(40)=0.0025

We move all terms to the left:

(2x^2)/(40)-(0.0025)=0

We add all the numbers together, and all the variables

2x^2/40-0.0025=0

We multiply all the terms by the denominator


2x^2-(0.0025)*40=0

We add all the numbers together, and all the variables

2x^2-0.1=0

a = 2; b = 0; c = -0.1;
Δ = b2-4ac
Δ = 02-4·2·(-0.1)
Δ = 0.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.8}}{2*2}=\frac{0-\sqrt{0.8}}{4}
=-\frac{\sqrt{}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.8}}{2*2}=\frac{0+\sqrt{0.8}}{4}
=\frac{\sqrt{}}{4}
$